Микроконтроллеры

Интересно, это юзабельно?

void FooTaskName0(unsigned int flags) { printf("From 0\n"); }
void FooTaskName1(unsigned int flags) {; }
void FooTaskName2(unsigned int flags) {; }

typedef void (*task_fun_ptr)(unsigned int flags);
typedef struct task_t{
  task_fun_ptr func;
  int rules;
}task_t;

#define TASKLIST \
	T(FooTaskName0) \
	T(FooTaskName1) \
	T(FooTaskName2) 

// потом использовать в функции как имя задачи
#define TASK(task) task##_enum

#define T(name)  FN(name) E(name)

#define FN(name)
#define E(name) name##_enum, 
enum t_itm{	TASKLIST TASKCOUNT };

#undef E
#define E(name)
#undef FN
#define FN(name) {.func=&name, .rules=0},
task_t task_collection[TASKCOUNT] = { TASKLIST };

Развернуло так:

void FooTaskName0(unsigned int flags) { printf("From 0\n"); }
void FooTaskName1(unsigned int flags) {; }
void FooTaskName2(unsigned int flags) {; }

typedef void (*task_fun_ptr)(unsigned int flags);
typedef struct task_t{
  task_fun_ptr func;
  int rules;
}task_t;
enum t_itm{ FooTaskName0_enum, FooTaskName1_enum, FooTaskName2_enum, TASKCOUNT };


task_t task_collection[TASKCOUNT] = { {.func=&FooTaskName0, .rules=0}, {.func=&FooTaskName1, .rules=0}, {.func=&FooTaskName2, .rules=0}, };