Микроконтроллеры

Можете проверить хоть все строчки :) Ну а для желающих побитно записать 32-х разрядное число есть макросы от Tom Torfs. Иногда лучше заставить компилятор немножко потрудиться. Tom Torfs Hello All, I've been missing the lack of support for binary numeric literals in C. To get around it I wrote the following handy macros, which allows you to simply write something like: whatever = B8(10101010); and will translate as: whatever = 85; (compile-time constant) Code below... hopefully it's useful to some of you as well. greetings, Tom /* Binary constant generator macro By Tom Torfs - donated to the public domain */ /* All macro's evaluate to compile-time constants */ /* *** helper macros *** / /* turn a numeric literal into a hex constant (avoids problems with leading zeroes) 8-bit constants max value 0x11111111, always fits in unsigned long */ #define HEX__(n) 0x##n##LU /* 8-bit conversion function */ #define B8__(x) ((x&0x0000000FLU)?1:0) \ +((x&0x000000F0LU)?2:0) \ +((x&0x00000F00LU)?4:0) \ +((x&0x0000F000LU)?8:0) \ +((x&0x000F0000LU)?16:0) \ +((x&0x00F00000LU)?32:0) \ +((x&0x0F000000LU)?64:0) \ +((x&0xF0000000LU)?128:0) //************************** /* *** user macros *** / /* for upto 8-bit binary constants */ #define B8(d) ((unsigned char)B8__(HEX__(d))) /* for upto 16-bit binary constants, MSB first */ #define B16(dmsb,dlsb) (((unsigned short)B8(dmsb)<<8) \ + B8(dlsb)) /* for upto 32-bit binary constants, MSB first */ #define B32(dmsb,db2,db3,dlsb) (((unsigned long)B8(dmsb)<<24) \ + ((unsigned long)B8(db2)<<16) \ + ((unsigned long)B8(db3)<<8) \ + B8(dlsb)) /* Sample usage: B8(01010101) = 85 B16(10101010,01010101) = 43605 B32(10000000,11111111,10101010,01010101) = 2164238933 */ greetings, Tom Nov 14 '05 #1